States of Aggregation of Matter
Solid, liquid, and gaseous states: crystal lattices, surface tension, viscosity, the ideal gas law and its extensions, and real gas behavior.
Complete Theory
4Solids are classified into crystalline (ordered periodic arrangement) and amorphous (disordered).
Crystalline solids by bond type:
Crystalline solids by bond type:
- Ionic (NaCl): high melting point, brittle, conductors when molten
- Covalent network (diamond, SiO₂): very hard, high
- Metallic (Cu, Fe): ductile, malleable, conductive
- Molecular (ice, I₂): low , soft, held by intermolecular forces
Liquids have a fixed volume but take the shape of the container. Key properties:
- Surface tension (): energy per unit area to increase the surface. Water has high surface tension due to hydrogen bonds.
- Viscosity (): resistance to flow. Increases with intermolecular force strength and molecular size.
- Capillary action: rise of a liquid in a narrow tube due to adhesion and cohesion.
The ideal gas law combines Boyle, Charles, and Avogadro:
where .
Dalton's law of partial pressures: the total pressure of a mixture of ideal gases equals the sum of the partial pressures of each component:
Dalton's law of partial pressures: the total pressure of a mixture of ideal gases equals the sum of the partial pressures of each component:
Real gases deviate from ideality at high pressure and low temperature because molecules have:
- Finite volume → corrected by (volume excluded per mole)
- Intermolecular attractions → corrected by (cohesion parameter)
Worked Examples
2Example 1Pressure of an ideal gas
Given
Find
Pressure exerted by the gas
Step-by-step solution
1Start from the ideal gas law and solve for pressure: .
2Substitute the given values: .
3Complete the division: .
✓ Final result:
Example 2Pressure with Van der Waals correction
Given
Same mol, L, K
Van der Waals constants ,
Find
Pressure using the Van der Waals equation
Step-by-step solution
1Solve the Van der Waals equation for : , where corrects for molecular volume and for intermolecular attractions.
2Plug in the values: .
3Calculate: , slightly lower than the ideal value due to intermolecular attractions.
✓ Final result: (vs. 4.93 atm ideal: small deviation)
Exercises with Solutions
3Exercise 1Dalton's lawMedium
Problem to solve
A 5.0 L container at 298 K holds 0.50 mol N₂ and 0.30 mol O₂. Calculate the partial pressures and the total pressure.
Given data
n(N₂) = 0.50 moln(O₂) = 0.30 molV = 5.0 LT = 298 K
Step-by-step solution
1
2
3
✓ Final answer: atm, atm, atm
Exercise 2Gas densityMedium
Problem to solve
Calculate the density of CO₂ (M = 44.0 g/mol) at 1.00 atm and 273 K.
Given data
M = 44.0 g/molP = 1.00 atmT = 273 K
Step-by-step solution
1
2
3
✓ Final answer:
Exercise 3Van der WaalsHard
Problem to solve
Calculate the volume occupied by 1.00 mol of Cl₂ at 10.0 atm and 300 K using the Van der Waals equation (, ).
Given data
n = 1.00 molP = 10.0 atmT = 300 Ka = 6.34 L²·atm·mol⁻²b = 0.0542 L·mol⁻¹
Step-by-step solution
1Solve iteratively
2Ideal guess: → correct with →
3The real volume is much smaller than ideal (24.6 L) due to strong intermolecular forces
✓ Final answer: (Van der Waals) vs. 24.6 L (ideal)
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