States of MatterMedium

Ideal gas law

Calculate the temperature (in °C) of 0.500 mol of gas occupying 12.0 L at 1.80 atm.
R = 0.08206 L·atm/(mol·K). PV = nRT.

Given data

P = 1.80 atmV = 12.0 Ln = 0.500 molR = 0.08206 L·atm/(mol·K)

Steps

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Calculate T = PV/(nR) in Kelvin.
Write your working — the numerical result must appear in the text K
Convert T from K to °C.

Full worked solution

Calculate T = PV/(nR) in Kelvin.
$\frac{1.80 \cdot 12.0}{0.500 \cdot 0.08206}$
$\frac{1.80 \cdot 12.0}{0.500 \cdot 0.08206} = (1.80\times12.0)/(0.500\times0.08206) = 526 = \mathbf{526\,K}$ . Temperature in Kelvin via ideal gas law.
Convert T from K to °C.
$526 - 273$
$526 - 273 = 253 = 253 = \mathbf{253\,°C}$ . Converted from Kelvin to Celsius.

Result:T = 526 K = 253 °C.

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