States of MatterMedium

Boyle's law — ideal gases

A gas occupies 2.50 L at 1.20 atm at constant temperature. Calculate the volume at 3.60 atm (Boyle: P₁V₁ = P₂V₂).

Given data

P₁ = 1.20 atmV₁ = 2.50 LP₂ = 3.60 atm

Steps

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Apply Boyle: calculate V₂ = P₁V₁/P₂.
Write your working — the numerical result must appear in the text L

Full worked solution

Apply Boyle: calculate V₂ = P₁V₁/P₂.
$\frac{1.20 \cdot 2.50}{3.60}$
$\frac{1.20 \cdot 2.50}{3.60} = (1.20\times2.50)/3.60 = 0.833 = \mathbf{0.833\,L}$ . Volume decreases with pressure by Boyle's law.

Result:V₂ = 0.833 L.

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