Chemical Thermodynamics
Energy changes in chemical reactions: internal energy, enthalpy, Hess's law, entropy, Gibbs free energy, and the criteria for spontaneity.
Complete Theory
5A thermodynamic system is the part of the universe under study; everything else is the surroundings.
Exothermic reactions release heat (). Endothermic reactions absorb heat ().
Energy is measured in joules (J) or calories (1 cal = 4.184 J).
Exothermic reactions release heat (). Endothermic reactions absorb heat ().
Energy is measured in joules (J) or calories (1 cal = 4.184 J).
The first law states that energy is conserved: (or depending on sign convention).
At constant pressure, the heat exchanged equals the enthalpy change: .
Standard enthalpy of formation : the enthalpy change when 1 mole of a compound is formed from its elements in their standard states.
At constant pressure, the heat exchanged equals the enthalpy change: .
Standard enthalpy of formation : the enthalpy change when 1 mole of a compound is formed from its elements in their standard states.
Hess's law: the enthalpy change of a reaction depends only on the initial and final states, not on the pathway. Therefore, we can sum the enthalpies of intermediate steps:
The second law: the entropy () of the universe increases in spontaneous processes. Entropy is a measure of disorder.
The third law: the entropy of a perfect crystal at is zero.
Standard molar entropies are tabulated. The entropy change of a reaction:
The third law: the entropy of a perfect crystal at is zero.
Standard molar entropies are tabulated. The entropy change of a reaction:
The Gibbs free energy combines enthalpy and entropy: . At constant :
Spontaneity criteria:
Spontaneity criteria:
- : spontaneous (exergonic)
- : non-spontaneous (endergonic)
- : equilibrium
Worked Examples
2Example 1Calculating from formation enthalpies
Given
Find
Standard reaction enthalpy
Step-by-step solution
1Apply Hess's law: , noting that elements in their standard state have .
2Substitute the values: .
3Calculate: , indicating an exothermic reaction.
✓ Final result: (exothermic)
Example 2Spontaneity via
Given
Find
at 298 K and the transition temperature
Step-by-step solution
1Use the Gibbs free energy equation , converting to joules: .
2Calculate: . Since , the reaction is spontaneous at 298 K.
3Find the transition temperature where : . Above this temperature, the reaction becomes non-spontaneous.
✓ Final result: at 298 K;
Exercises with Solutions
3Exercise 1Heat at constant pressureMedium
Problem to solve
How much heat is released when 4.0 g of CH₄ (M = 16 g/mol) is burned? .
Given data
m = 4.0 gM = 16 g/mol kJ/mol
Step-by-step solution
1 mol
2
✓ Final answer: −222.5 kJ (heat released)
Exercise 2Hess's lawMedium
Problem to solve
Given: kJ; kJ. Find for .
Given data
C + O₂ → CO₂: −393.5 kJCO + ½O₂ → CO₂: −283.0 kJ
Step-by-step solution
1Reverse the second: kJ
2Add the first: kJ
3Sum:
✓ Final answer:
Exercise 3Spontaneity transition temperatureHard
Problem to solve
For kJ and J/K, determine the temperature above which the reaction becomes spontaneous.
Given data
kJ J/K
Step-by-step solution
1; spontaneous when
2
3
✓ Final answer: Spontaneous above 1113 K (endothermic driven by entropy)
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