ThermochemistryMedium

Heat capacity and specific heat

How much heat is needed to heat 500 g of water from 20 °C to 80 °C?
c_H₂O = 4.184 J/(g·°C). q = m·c·ΔT.

Given data

m = 500 gT₁ = 20 °CT₂ = 80 °Cc = 4.184 J/(g·°C)

Steps

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Calculate ΔT = T₂ - T₁.
Write your working — the numerical result must appear in the text °C
Calculate q = m·c·ΔT.

Full worked solution

Calculate ΔT = T₂ - T₁.
$80 - 20$
$80 - 20 = 60 = 60 = \mathbf{60\,°C}$ . Temperature difference calculated.
Calculate q = m·c·ΔT.
$500 \cdot 4.184 \cdot 60$
$500 \cdot 4.184 \cdot 60 = 500\times4.184\times60 = 125520 = \mathbf{125520\,J}$ . Heat required to warm the water.

Result:q = 125.5 kJ.

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