AromaticityMedium

Hückel rule

A planar, conjugated ring has 10 π electrons. For which value of n does it satisfy Hückel's rule (4n+2)?

Given data

π electrons = 10

Steps

0 / 1

A planar, conjugated ring is aromatic only if its π electrons number 4n+2 (with n an integer ≥ 0): it is this filling that gives aromatic stability. So I set 4n+2 equal to the number of π electrons and check that n comes out an integer.
Write your working — the numerical result must appear in the text

Full worked solution

A planar, conjugated ring is aromatic only if its π electrons number 4n+2 (with n an integer ≥ 0): it is this filling that gives aromatic stability. So I set 4n+2 equal to the number of π electrons and check that n comes out an integer.
$4n + 2 = 10$
$4n+2 = 10 \Rightarrow n = 2$ . n is an integer → the ring is aromatic ( $\mathbf{n=2}$ ).

Result:

n = 2

(aromatic)

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