Chemical EquilibriaHard

pH of a weak acid

Calculate the pH of 0.100 M acetic acid (CH₃COOH, Ka = 1.8×10⁻⁵).
CH₃COOH ⇌ CH₃COO⁻ + H⁺.
Given data
[HA]₀ = 0.100 MK<sub>a</sub> = 1.8×10⁻⁵
Review the theory: Equilibri e pH
Steps
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  1. Write Ka expression for acetic acid.
  2. Approximate x = [H⁺] at equilibrium. Ka ≈ x²/0.100. Find x.
  3. Calculate pH = -log₁₀([H⁺]).
Full worked solution
  1. Write Ka expression for acetic acid.
    Ka=[H+][A−][HA]K_a = \frac{[H^+][A^-]}{[HA]}
    K_a = [H⁺][A⁻]/[HA] = 1.8×10⁻⁵.
  2. Approximate x = [H⁺] at equilibrium. Ka ≈ x²/0.100. Find x.
    1.8×10−5⋅0.100\sqrt{1.8\times10^{-5}\cdot0.100}
    x = √(1.8×10⁻⁶) = 1.34×10⁻³ M.
  3. Calculate pH = -log₁₀([H⁺]).
    −log⁡10(0.00134)-\log_{10}(0.00134)
    pH = -log(1.34×10⁻³) = 2.87.
Result:pH = 2.87 (weak acid).