LimitsMedium

Notable limit with sin(ax)/(bx)

Calculate lim_{x→0} sin(4x)/(2x) using the fundamental notable limit.
Given data
lim_{x→0} sin(4x)/(2x)
Review the theory: Limiti
Steps
0 / 3
  1. Rewrite the expression to reveal the notable limit sin(t)/t → 1.
  2. What is the limit of sin(4x)/(4x) as x→0?
  3. Therefore the total limit equals?
Full worked solution
  1. Rewrite the expression to reveal the notable limit sin(t)/t → 1.
    sin⁡(4x)2x=42⋅sin⁡(4x)4x\dfrac{\sin(4x)}{2x} = \dfrac{4}{2} \cdot \dfrac{\sin(4x)}{4x}
    sin⁡(4x)2x=42⋅sin⁡(4x)4x=2⋅sin⁡(4x)4x\frac{\sin(4x)}{2x} = \frac{4}{2} \cdot \frac{\sin(4x)}{4x} = 2 \cdot \frac{\sin(4x)}{4x}. We factor the expression to reveal the fundamental notable limit sin⁡(t)/t→1\sin(t)/t \to 1.
  2. What is the limit of sin(4x)/(4x) as x→0?
    lim⁡t→0sin⁡tt=1\lim_{t\to 0} \dfrac{\sin t}{t} = 1
    Let t=4xt = 4x. As x→0x \to 0, t→0t \to 0. The fundamental notable limit gives lim⁡t→0sin⁡tt=1\displaystyle\lim_{t\to 0} \frac{\sin t}{t} = \mathbf{1}.
  3. Therefore the total limit equals?
    2⋅1=22 \cdot 1 = 2
    lim⁡x→0sin⁡(4x)2x=2×1=2\displaystyle\lim_{x\to 0} \frac{\sin(4x)}{2x} = 2 \times 1 = \mathbf{2}. The coefficient 2 multiplied by the notable limit gives the result.
Result:lim_{x→0} sin(4x)/(2x) = 2.