ElectrochemistryMedium

Nernst equation

Calculate cell potential for Zn²⁺(0.010 M)/Zn: E° = -0.76 V.
Use Nernst: E = E° - (0.0592/n)·log(Q). T = 298 K.

Given data

E° = -0.76 V[Zn²⁺] = 0.010 Mn = 2 (Zn²⁺ + 2e⁻ → Zn)

Steps

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Calculate log(Q) where Q = 1/[Zn²⁺] for reduction.
Write your working — the numerical result must appear in the text
Calculate E = E° - (0.0592/n)·log(Q).

Full worked solution

Calculate log(Q) where Q = 1/[Zn²⁺] for reduction.
$\log\left(\frac{1}{0.010}\right)$
log(100) = 2.
Calculate E = E° - (0.0592/n)·log(Q).
$-0.76 - \frac{0.0592}{2} \cdot 2$
E = -0.76 - (0.0592/2)×2 = -0.76 - 0.0592 = -0.819 V.

Result:E = -0.819 V.

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