Uningenia
Start studyingStart
Phase Changes and DiagramsMedium

Heating curve — ice to steam

Calculate total heat to bring 50.0 g of ice at -10 °C to steam at 110 °C.
cice = 2.09 J/(g·°C), ΔHfus = 334 J/g, cwater = 4.184 J/(g·°C), ΔHvap = 2260 J/g, csteam = 2.01 J/(g·°C).
Given data
m = 50.0 gc_ice = 2.09 J/(g·°C)ΔH_fus = 334 J/gc_water = 4.184 J/(g·°C)ΔH_vap = 2260 J/gc_steam = 2.01 J/(g·°C)
Review the theory: Equilibri tra Fasi
Steps
0 / 6
  1. Calculate q₁ to heat ice from -10 °C to 0 °C.
  2. Calculate q₂ to melt the ice.
  3. Calculate q₃ to heat water from 0 °C to 100 °C.
  4. Calculate q₄ to vaporize the water.
  5. Calculate q₅ to heat steam from 100 °C to 110 °C.
  6. Calculate qtot.
Full worked solution
  1. Calculate q₁ to heat ice from -10 °C to 0 °C.
    50.0⋅2.09⋅1050.0 \cdot 2.09 \cdot 10
    q₁ = 50.0 × 2.09 × 10 = 1045 J.
  2. Calculate q₂ to melt the ice.
    50.0⋅33450.0 \cdot 334
    q₂ = 50.0 × 334 = 16,700 J.
  3. Calculate q₃ to heat water from 0 °C to 100 °C.
    50.0⋅4.184⋅10050.0 \cdot 4.184 \cdot 100
    q₃ = 50.0 × 4.184 × 100 = 20,920 J.
  4. Calculate q₄ to vaporize the water.
    50.0⋅226050.0 \cdot 2260
    q₄ = 50.0 × 2260 = 113,000 J.
  5. Calculate q₅ to heat steam from 100 °C to 110 °C.
    50.0⋅2.01⋅1050.0 \cdot 2.01 \cdot 10
    q₅ = 50.0 × 2.01 × 10 = 1005 J.
  6. Calculate qtot.
    1045+16700+20920+113000+10051045 + 16700 + 20920 + 113000 + 1005
    q_tot = 152,670 J = 152.7 kJ.
Result:qtot = 152.7 kJ.
TheoryEquilibri tra FasiFormula sheetChemistry

Similar exercises