◈ Termodinamica
Gas perfetti, trasformazioni termodinamiche, I e II principio, macchine termiche, cicli di Carnot e Otto, entropia.
Complete Theory
Worked Examples
Example 1Isobaric process — A gas expanding at constant pressure
Example 2RMS speed of nitrogen at 300 K — How fast are molecules?
Exercises with Solutions
Exercise 1Compound process (isobaric + isochoric)Hard
📋 Problem to solve
A monatomic gas ( mol, ) undergoes: A( K, atm) →isobaric→ B( K) →isochoric→ C( atm). Find total work and total internal energy change .
📌 Given data
n=3 molC_v=3R/2P_A = P_B = 2 atm (isobar)V_B = V_C (isochore)
Exercise 2Dalton's law — Gas mixturesHard
📋 Problem to solve
A container of volume L at K holds mol of O₂ and mol of N₂. Find total pressure, partial pressures, and mole fractions.
📌 Given data
V=0.010 m³T=300 Kn_O₂=0.5 moln_N₂=1.2 mol
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Integrative Problems
Problems combining all chapters — exam levelProblem 1The Thermoelectric Power Plant: from Gas to Molecules to EntropyEXTREME
A thermoelectric power plant uses of a diatomic gas (, ) running through the following cycle on a PV diagram:
State A: , . A→B: adiabatic compression to (compression ratio ). B→C: isochoric, heating to (combustion). C→D: adiabatic expansion to (return to original volume). D→A: isochoric, cooling (Otto cycle).
State A: , . A→B: adiabatic compression to (compression ratio ). B→C: isochoric, heating to (combustion). C→D: adiabatic expansion to (return to original volume). D→A: isochoric, cooling (Otto cycle).
📌 Problem data
n = 5\,\mathrm{mol}\gamma = 7/5 = 1.4,\; C_v = 5R/2T_A = 300\,\mathrm{K},\; P_A = 1\,\mathrm{atm}r = V_A/V_B = 8T_C = 2400\,\mathrm{K}
(a)Ideal Gas — Thermodynamic States(b)First Law — Work and Heat for Each Process(c)Cycles — Otto vs Carnot Efficiency(d)Kinetic Theory — Molecules in Motion(e)Entropy — Second Law and Global Balance
