◈ Termodinamica
Gas perfetti, trasformazioni termodinamiche, I e II principio, macchine termiche, cicli di Carnot e Otto, entropia.
Complete Theory
Worked Examples
Example 1Carnot engine — Maximum efficiency calculation
Example 2Otto cycle — Efficiency of a spark-ignition engine
Exercises with Solutions
Exercise 1Real engine vs Carnot — How far from the limit?Hard
📋 Problem to solve
A heat engine operates between K and K. It absorbs kJ and produces kJ. Compute: (a) real efficiency ; (b) Carnot efficiency ; (c) entropy change of the universe .
📌 Given data
T_H=650 KT_C=290 KQ_H=8000 JW=2800 J
Exercise 2Refrigerator — How much energy is needed to cool?Hard
📋 Problem to solve
A refrigerator maintains its interior at in a room at . It must remove kJ/h from the interior. Compute: (a) maximum theoretical COP; (b) minimum required power; (c) heat rejected to the room.
📌 Given data
T_C=276 KT_H=308 KQ_C=200000 J/h
Recommended Books
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Integrative Problems
Problems combining all chapters — exam levelProblem 1The Thermoelectric Power Plant: from Gas to Molecules to EntropyEXTREME
A thermoelectric power plant uses of a diatomic gas (, ) running through the following cycle on a PV diagram:
State A: , . A→B: adiabatic compression to (compression ratio ). B→C: isochoric, heating to (combustion). C→D: adiabatic expansion to (return to original volume). D→A: isochoric, cooling (Otto cycle).
State A: , . A→B: adiabatic compression to (compression ratio ). B→C: isochoric, heating to (combustion). C→D: adiabatic expansion to (return to original volume). D→A: isochoric, cooling (Otto cycle).
📌 Problem data
n = 5\,\mathrm{mol}\gamma = 7/5 = 1.4,\; C_v = 5R/2T_A = 300\,\mathrm{K},\; P_A = 1\,\mathrm{atm}r = V_A/V_B = 8T_C = 2400\,\mathrm{K}
(a)Ideal Gas — Thermodynamic States(b)First Law — Work and Heat for Each Process(c)Cycles — Otto vs Carnot Efficiency(d)Kinetic Theory — Molecules in Motion(e)Entropy — Second Law and Global Balance
