Ideal Fluid Dynamics
Continuity equation, Bernoulli's theorem, and applications: Venturi tube, Torricelli, aerodynamic lift.
Complete Theory
4To simplify the study of moving fluids we introduce the ideal fluid model:
Steady flow: the fluid properties (velocity, pressure, density) at every point do not change with time: . Streamlines are curves whose tangent at every point indicates the velocity direction. In steady flow, streamlines coincide with trajectories and never intersect.
Laminar vs turbulent flow:
Real-world examples:
- Incompressible (): density does not vary with pressure. Real liquids approximate this condition well at moderate speeds.
- Non-viscous (): no internal friction between fluid layers. In reality all fluids have some viscosity (water, air), but for many problems its effect is negligible.
Steady flow: the fluid properties (velocity, pressure, density) at every point do not change with time: . Streamlines are curves whose tangent at every point indicates the velocity direction. In steady flow, streamlines coincide with trajectories and never intersect.
Laminar vs turbulent flow:
- Laminar: the fluid flows in orderly, parallel layers. Typical at low speeds and in narrow conduits (e.g., dripping honey).
- Turbulent: the motion is chaotic with vortices and fluctuations. Typical at high speeds and wide conduits (e.g., water from a fire hydrant).
Real-world examples:
- Faucet: at moderate flow the water comes out laminar (clear jet); opening fully makes it turbulent (white jet due to air bubbles).
- Cigarette smoke: initially rises in laminar flow, then becomes turbulent.
- Blood flow: in healthy arteries flow is laminar; heart murmurs indicate turbulence.
The continuity equation expresses mass conservation. For an incompressible fluid, the volumetric flow rate (volume passing through a cross-section per unit time) is constant:
If the cross-section narrows, the velocity increases proportionally, and vice versa: .
For a compressible fluid, the mass flow rate is conserved: .
Intuitive interpretation: imagine squeezing the end of a garden hose — the water comes out faster because the same amount of water must pass through a smaller opening in the same time.
Real-world applications and examples:
For a compressible fluid, the mass flow rate is conserved: .
Intuitive interpretation: imagine squeezing the end of a garden hose — the water comes out faster because the same amount of water must pass through a smaller opening in the same time.
Real-world applications and examples:
- Fire hose: squeezing the nozzle reduces the exit area, increasing water velocity and range.
- River: where the riverbed narrows the current accelerates; where it widens it slows down.
- Blood circulation: blood velocity decreases in capillaries (huge total cross-section) and increases in arteries (small cross-section).
- Ventilation ducts: grilles use narrowing to accelerate air.
- Venturi tubes: use constriction to measure flow rate.
Bernoulli's theorem follows from the conservation of mechanical energy along a streamline of an ideal fluid in steady flow:
Interpretation of the three terms (energy per unit volume):
Key consequence: at the same elevation, where velocity increases pressure decreases, and vice versa. This is the Bernoulli effect, underlying numerous phenomena and applications.
Real-world applications and examples:
Interpretation of the three terms (energy per unit volume):
- — static pressure: energy associated with pressure forces.
- — dynamic pressure: kinetic energy per unit volume.
- — gravity pressure: gravitational potential energy per unit volume.
Key consequence: at the same elevation, where velocity increases pressure decreases, and vice versa. This is the Bernoulli effect, underlying numerous phenomena and applications.
Real-world applications and examples:
- Aerodynamic lift: an airplane wing has an asymmetric profile. Air on the upper surface flows faster (longer path), creating a low-pressure zone above the wing. The pressure difference generates an upward force (lift).
- Carburetor: the narrowing of the air duct creates a depression that draws fuel from the reservoir.
- Atomizer (perfume): squeezing the bulb creates a fast air jet above a vertical tube; the low pressure draws the liquid, which is atomized.
- Curveball (Magnus effect): the ball's rotation creates an air speed difference on opposite sides, curving the trajectory.
- Roof torn off by wind: strong wind over a roof creates a low-pressure zone; the higher internal pressure can lift the roof.
- Chimney: wind at the chimney top creates a depression that enhances smoke extraction.
Torricelli's theorem — efflux from a tank:
Consider a tank with a hole at depth below the free surface. Applying Bernoulli between the free surface (, ) and the hole ():
The efflux velocity is identical to that of a body in free fall from height . The flow rate through the hole is .
Venturi tube — flow rate meter: A conduit with a central constriction. Applying Bernoulli and continuity between sections 1 (wide) and 2 (narrow), the flow rate is obtained from the pressure difference: Combining with yields and thus .
Aerodynamic lift in detail: The wing has an asymmetric profile: the upper surface is more curved than the lower surface. Streamlines bunch together above the wing, increasing velocity and decreasing pressure. The difference generates a net upward force: where is the lift coefficient (dependent on wing shape and angle of attack), the air density, the wing area, and the flight speed.
Other applications:
Venturi tube — flow rate meter: A conduit with a central constriction. Applying Bernoulli and continuity between sections 1 (wide) and 2 (narrow), the flow rate is obtained from the pressure difference: Combining with yields and thus .
Aerodynamic lift in detail: The wing has an asymmetric profile: the upper surface is more curved than the lower surface. Streamlines bunch together above the wing, increasing velocity and decreasing pressure. The difference generates a net upward force: where is the lift coefficient (dependent on wing shape and angle of attack), the air density, the wing area, and the flight speed.
Other applications:
- Siphon: uses pressure difference to transfer liquid from one level to another through a tube.
- Venturi meter: flow measurement in industrial pipes, oil pipelines, aqueducts.
- Drain time: integrating the flow rate yields the time needed to drain a tank.
Worked Examples
2Example 1Venturi tube — flow rate measurement
Given
m (wide section diameter)
m (narrow section diameter)
Pa (pressure difference)
kg/m³ (water density)
Find
Velocity in the wide section
Velocity in the narrow section
Volumetric flow rate
Step-by-step solution
1Compute the areas of the two sections: m², m². The ratio means the wide section is 6.25 times larger than the narrow one. From the continuity equation , we get .
2Apply Bernoulli between the two sections (same elevation, so the term cancels): . The measured pressure difference is where . Solving for : m/s.
3From continuity: m/s. The volumetric flow rate is m³/s, equivalent to litres per second (recalling m³ L).
✓ Final result: m/s, m/s, L/s
Example 2Torricelli's theorem — jet range
Given
m (height of free surface above hole)
cm² (area of the efflux hole)
Find
Efflux velocity from the hole
Flow rate through the hole
Horizontal range of the jet (if the hole is on the side of the tank)
Step-by-step solution
1By Torricelli's theorem, the efflux velocity is m/s. Physically, the gravitational potential energy of the fluid at the free surface () is fully converted into kinetic energy at the outlet (), just like a body in free fall. This conversion is complete because we assume an ideal fluid (no friction).
2The flow rate is the product of the hole area and the efflux velocity. Convert the area to square metres: cm² m². Hence m³/s. In litres per second: L/s (about 2 litres of water exit every second).
3For a horizontal jet, the fall time from the hole to the ground depends only on the hole height : s. The horizontal range is m. Remarkably, the range equals twice the height and does not depend on !
✓ Final result: m/s, L/s, range m
Exercises with Solutions
2Exercise 1Bernoulli with elevationHard
Problem to solve
Water flows in a horizontal conduit that then rises to m. In section 1 (elevation ): cm², Pa, m/s. In section 2: cm², m. Find and (water density kg/m³).
Given data
A_1=50 cm² (section 1)P_1=2×10⁵ Pa (pressure at 1)v_1=1.5 m/s (velocity at 1)A_2=20 cm², z_2=3 m (section 2 and elevation)ρ=1000 kg/m³ (water)
Step-by-step solution
1From the continuity equation: . Convert areas to m²: m², m². Thus m/s. The velocity increases because the cross-section narrows.
2Apply Bernoulli with elevation (presence of the term): . With , we get .
3Compute the terms: Pa (dynamic pressure decreases because ). The elevation term Pa. Therefore Pa Pa.
✓ Final answer: m/s, Pa
Exercise 2Tank drainingVery Hard
Problem to solve
A cylindrical tank of diameter m has a hole of diameter cm located at m from the bottom. The initial water level is m from the bottom. (a) Calculate the drain time. (b) Determine the initial jet range (consider the hole on the side, at m from the ground).
Given data
D=2 m (tank diameter)d=0.04 m (hole diameter)z_hole=0.5 m (hole height from ground)H_0=4 m (initial water level)
Step-by-step solution
1The initial hydraulic head is m. The initial efflux velocity from Torricelli is m/s. The ratio of the tank area m² to the hole area m² is about .
2The drain time is obtained by integrating the differential equation from mass conservation: . Separating variables and integrating from to : s, which is about 35 minutes and 12 seconds.
3The initial jet range is computed as for a horizontal jet: the fall time from the hole to the ground is s. The initial range is m. Note that the range decreases as the water level drops.
✓ Final answer: s min 12 s; initial jet range m
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Integrative Problems
Problems combining all chapters — exam levelProblem 1The Dam, the Hydraulic Conduit, and the Water JetEXTREME
A dam holds back an artificial lake. The water () reaches a height above the lowest point of the dam. The wall is wide.
At from the bottom there is a valve connected to a conduit that transitions from cross-section to a constriction (Venturi tube), then widens again and terminates at with a nozzle of area .
At from the bottom there is a valve connected to a conduit that transitions from cross-section to a constriction (Venturi tube), then widens again and terminates at with a nozzle of area .
📌 Problem data
(a)Hydrostatics — Stevin + Total Force(b)Hydrostatics + Torricelli(c)Fluid Dynamics — Bernoulli + Venturi(d)Bernoulli with Elevation — Nozzle at Height(e)Hydraulic Power — Archimedes + Work