Fluids
Hydrostatics and hydrodynamics of ideal fluids: Pascal, Stevin, Archimedes and Bernoulli laws, with applications. Every topic with step-by-step theory, interactive diagrams and solved exercises.
Complete Theory
4A fluid is a substance that continuously deforms under the action of a shear stress, no matter how small. Unlike solids, fluids have no fixed shape and conform to the shape of their container. Both gases and liquids are fluids.
Pressure is a scalar quantity defined as the ratio of the normal force exerted on a surface to the area of that surface: . In the International System it is measured in pascals (Pa), where . Other common units include the atmosphere (), the millimeter of mercury (), and the bar ().
In fluids at rest, pressure is isotropic: it acts with equal intensity in all directions. At any point in the fluid, the force on a small surface element is always perpendicular to the surface and has the same magnitude regardless of orientation.
Difference between liquids and gases:
Everyday examples:
Pressure is a scalar quantity defined as the ratio of the normal force exerted on a surface to the area of that surface: . In the International System it is measured in pascals (Pa), where . Other common units include the atmosphere (), the millimeter of mercury (), and the bar ().
In fluids at rest, pressure is isotropic: it acts with equal intensity in all directions. At any point in the fluid, the force on a small surface element is always perpendicular to the surface and has the same magnitude regardless of orientation.
Difference between liquids and gases:
- Incompressible (): density is constant. Volume does not change appreciably with pressure. Typical of liquids (water, oil, mercury).
- Compressible ( varies with and ): density depends on pressure and temperature according to an equation of state. Typical of gases (air, steam).
Everyday examples:
- Dams: water pressure increases with depth, which is why dams are built thicker at the base.
- Underwater pressure: at 10 m depth total pressure is about 2 atm (1 atm atmospheric + 1 atm hydrostatic).
- Drinking with a straw: by sucking we lower the pressure in our mouth, and atmospheric pressure pushes the liquid up.
- Atmospheric pressure: decreases with altitude; aircraft cabins are pressurized to maintain a comfortable pressure.
Pascal's principle states that a pressure change applied to an incompressible fluid confined in a container is transmitted undiminished and instantaneously to every point in the fluid and to the container walls.
Hydraulic press: two connected cylinders of area and , filled with fluid (usually oil). Applying on the small piston generates , which is transmitted unchanged to the large piston, producing . The ratio is called the mechanical advantage and can be very large (tens or hundreds).
Energy conservation: . Since , it follows that : what is gained in force is lost in displacement.
Real-world applications:
Hydraulic press: two connected cylinders of area and , filled with fluid (usually oil). Applying on the small piston generates , which is transmitted unchanged to the large piston, producing . The ratio is called the mechanical advantage and can be very large (tens or hundreds).
Energy conservation: . Since , it follows that : what is gained in force is lost in displacement.
Real-world applications:
- Hydraulic brakes: the force of the foot on the pedal is multiplied to actuate the brake pads.
- Car lifts: a small piston lifts vehicles weighing tons.
- Excavators and cranes: hydraulic arms that lift heavy loads.
- Dentist chairs and barber chairs: height adjustment using hydraulic systems.
- Earthmoving machinery: shovels and buckets operated by high-pressure hydraulic circuits.
Stevin's law (the fundamental law of hydrostatics) describes pressure in a fluid at rest under gravity. Considering a fluid column of density and height :
where is the pressure at the free surface (typically atmospheric pressure), is the fluid density, m/s² is the gravitational acceleration, and is the depth from the surface.
Key properties:
Communicating vessels: containers connected at the base reach the same liquid level regardless of shape, because the pressure at the base must be the same in all branches: . If the fluids differ, the heights are inversely proportional to the densities.
Real-world applications and examples:
Key properties:
- Pressure increases linearly with depth: .
- It depends only on depth and fluid density, not on container shape (hydrostatic paradox).
- Two points at the same depth in a homogeneous fluid have the same pressure.
Communicating vessels: containers connected at the base reach the same liquid level regardless of shape, because the pressure at the base must be the same in all branches: . If the fluids differ, the heights are inversely proportional to the densities.
Real-world applications and examples:
- Dams: pressure grows with depth; dams have a triangular cross-section, wider at the base to withstand the greater pressure.
- Submarines: at 100 m depth pressure is Pa (10 atm). The hull must be extremely strong.
- Water towers: in water supply systems, the tower height determines the pressure in the pipes.
- Mercury barometer: the mercury column is supported by atmospheric pressure: .
- Blood pressure: the heart pumps blood generating a pressure that varies with body position relative to the heart.
Archimedes' principle: a body immersed in a fluid experiences an upward buoyant force equal to the weight of the displaced fluid:
Physical origin: the buoyant force arises from the pressure difference between the lower and upper parts of the body (Stevin's law). The greater pressure at the bottom generates a net upward force.
Floating conditions:
Real-world applications and examples:
Physical origin: the buoyant force arises from the pressure difference between the lower and upper parts of the body (Stevin's law). The greater pressure at the bottom generates a net upward force.
Floating conditions:
- : the body floats (wood on water).
- : neutral equilibrium (suspended at any depth).
- : the body sinks (iron in water).
Real-world applications and examples:
- Ships: a steel ship floats because its average density (including air in the holds) is lower than that of water.
- Submarines: control submersion by filling or emptying ballast tanks with water.
- Hot air balloons: hot air has lower density than the surrounding air, generating an upward buoyant force.
- Hydrometers: instruments that measure liquid density using the flotation of a graduated float.
- Icebergs: about 90% of the volume is submerged ( kg/m³, kg/m³).
- Apparent weight: a submerged object feels lighter; the difference between real weight and apparent weight is the buoyant force.
Worked Examples
2Example 1Buoyant force on aluminium cube
Given
m (cube edge)
kg/m³ (aluminium density)
kg/m³ (water density)
Find
Weight of the cube in air
Buoyant force when fully submerged
Apparent weight underwater
Step-by-step solution
1Compute the cube volume: . Using aluminium density kg/m³, we find the mass: kg. The weight in air is therefore N. This is the force measured by a dynamometer when the cube is suspended in air.
2When the cube is fully immersed in water, it displaces a volume of water equal to its own volume m³. By Archimedes' principle, the upward buoyant force equals the weight of the displaced water: N. This force opposes the weight, reducing the tension in the dynamometer.
3The apparent weight underwater is the difference between the real weight and the buoyant force: N. This is the value read on the dynamometer when the cube is submerged. We can verify that the ratio matches .
✓ Final result: N, N, N
Example 2Hydraulic press — lifting a car
Given
cm² (small piston area)
cm² (large piston area)
Car weight N (about 1224 kg)
Find
Minimum force required on the small piston
Displacement of the small piston if the large one rises cm
Step-by-step solution
1By Pascal's principle, pressure is transmitted undiminished through the fluid: . Solving for : N. The mechanical advantage is : the force is multiplied 80 times. With a force of only 150 N (equivalent to lifting about 15 kg) we can lift a 12000 N car!
2Work is conserved (energy conservation): . Solving for : m. The small piston travels 80 times the distance of the large one: 1.6 meters versus 2 cm. This is the trade-off for the mechanical advantage.
3Numerical verification of energy conservation: J, J. The two work values are identical, confirming that the press multiplies force but not work, in agreement with the principle of conservation of mechanical energy.
✓ Final result: N, m
Exercises with Solutions
2Exercise 1Partially submerged bodyHard
Problem to solve
A block of volume m³ floats on water with 60% of its volume submerged. (a) Determine the density of the block. (b) If an additional mass kg is placed on top of the block, what percentage of the volume remains above water?
Given data
V=2×10⁻³ m³60% submerged (initial condition)ρ_H₂O=1000 kg/m³m_p=0.5 kg (added mass)
Step-by-step solution
1For a floating body, weight is balanced by the buoyant force: . Cancelling : . The block mass is kg. The block density is therefore kg/m³.
2Adding kg, the total mass becomes kg. The new equilibrium requires , so m³.
3The submerged percentage is . The percentage above water is .
✓ Final answer: kg/m³; with the added weight, 15% of the block volume remains above water
Exercise 2Torricelli barometerHard
Problem to solve
A mercury barometer reads a height mm. (a) Calculate the atmospheric pressure in pascals. (b) What height would a water barometer have under the same conditions? (c) On a planet with m/s², how many mm of Hg would the same barometer read (same Earth )?
Given data
h=0.762 m (Hg column height)ρ_Hg=13600 kg/m³ (mercury density)g=9.81 m/s² (Earth gravity)g_p=3.7 m/s² (planetary gravity)
Step-by-step solution
1Atmospheric pressure balances the mercury column: Pa Pa, which is about 1 atm (101325 Pa). The small difference is due to the 762 mm height instead of the standard 760 mm.
2For a water barometer (same ): , so m. Water is about 13.6 times less dense than mercury, so the column must be 13.6 times taller. This is why mercury is preferred in barometers: a water column would require a tube over 10 meters tall!
3On the planet with m/s², using the same Earth : m mm. With weaker gravity, a taller mercury column is needed to balance the same atmospheric pressure.
✓ Final answer: kPa; water barometer m; on the planet m
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Integrative Problems
Problems combining all chapters — exam levelProblem 1The Dam, the Hydraulic Conduit, and the Water JetEXTREME
A dam holds back an artificial lake. The water () reaches a height above the lowest point of the dam. The wall is wide.
At from the bottom there is a valve connected to a conduit that transitions from cross-section to a constriction (Venturi tube), then widens again and terminates at with a nozzle of area .
At from the bottom there is a valve connected to a conduit that transitions from cross-section to a constriction (Venturi tube), then widens again and terminates at with a nozzle of area .
📌 Problem data
(a)Hydrostatics — Stevin + Total Force(b)Hydrostatics + Torricelli(c)Fluid Dynamics — Bernoulli + Venturi(d)Bernoulli with Elevation — Nozzle at Height(e)Hydraulic Power — Archimedes + Work